Earlier today I have set the next problem that includes Albert, Bernard and Cherlell, the heroes in A. Viral puzzle a decade ago. Here is again with the solution.
Sherrill’s home number problem
Sherrill: I thought about two of two distinctive numbers, one. The last number of numbers is the last number of Bernard’s home number. What is the sum of these two numbers?
Albert: I don’t know what Bernard’s home number is.
Bernard: I know a home number, of course, and I know what is the total number of numbers.
Albert: Initially, I didn’t know what is the total number of numbers, but I know now.
What is the total number of numbers?
solution 10
Let two Sherrill numbers be A and for. Below is the possible values schedule for the final number dadWith the potential couples whose product holds this final number, and the potential amounts A + for .
Say that Bernard’s home number ends in 2. Sherrill may have thought of 1 and 2 (1 x 2 = 2), or 3 and 4 (3 x 4 = 12), or 8 and 9 (8 x 9 = 72). So the amount A + for It can be 3, 7, 17 and so on. Bernard cannot know 100 percent of the value A + for.
The only time in which Bernard can know is that the amount is when there is only one possibility A + for. If you look at the table, then the only time A + for Unique is when the last number is 1 or 9. In both cases, the amount is 10.
At the end of the operation, we do not know Sherrill numbers. We just know their sum.
I hope you enjoyed the language – I will return within two weeks.
If you want to see the solution to the Sherrill birthday problem, Click here.
Thanks to Joseph Yio on the mystery of today.
I have prepared a mystery here on Mondays since 2015. I have always been aware of the wonderful puzzles. If you want one suggestion, Send me.
